Create 45 degree cut with the EXTRUDE function

[ladjr]

I was thinking that you can compute the angle if you have the two sides. For example if your board is .5 inches and the cut is .7 inches long you would have a 45.58 degree angle, Has any one tried this

[AskBud]

I was thinking that you can compute the angle if you have the two sides. For example if your board is .5 inches and the cut is .7 inches long you would have a 45.58 degree angle, Has any one tried this

You may set the grid size as needed (within Extrude), set the Snap-to-grid function. From there, you need only draw your extrude line (for your 45 degree) from one corner to the opposite corner. Then just continue your extrude layout as desired.
AskBud

[ladjr]

I was trying to find out if anyone had tried this and how the angles turned out.

[AskBud]

I was trying to find out if anyone had tried this and how the angles turned out.

Your math may be off! You can use designer to see the results by activating the Snap-to-grid function. From there you can draw your connected lines to scale, assuring your right angle. I used 7 and 5 inches. The attached picture shows the figure in designer. The math shows one angle at 54.5 so the smaller angle must be 35.5.
AskBus

[ladjr]

Your math may be off! You can use designer to see the results by activating the Snap-to-grid function. From there you can draw your connected lines to scale, assuring your right angle. I used 7 and 5 inches. The attached picture shows the figure in designer. The math shows one angle at 54.5 so the smaller angle must be 35.5.
AskBus

Your number is correct, but I used .5 for the height and .7 for the Hipotinoze( Been a long time since geometry class) that would give you the 45.58 degree. We can set the thickness of the board = .5 and the length of the cut .7.

[bluecobra]

Your number is correct, but I used .5 for the height and .7 for the Hipotinoze( Been a long time since geometry class) that would give you the 45.58 degree. We can set the thickness of the board = .5 and the length of the cut .7.

A right triangle has a base, height & hypotenuse.

If you're looking for 45° angles, both the base & height need to be the same length (also known as an isosceles triangle).

If you want a 45° bevel, make the base .5" long and make the height .5" high or adjust accordingly.

If you need the length of the hypotenuse, you have to trig it out, I think that involves pythagorean theorem (a²+b²=c², where c² is the hypotenuse). So for a .5" triangle it'd be .707.

*i miss my machining days

[cnsranch]

Forget all that, Mark - here's the REAL answer.....

Recruit Superman to make the last mile - he can travel faster than the speed of sound, making time not only stand still, but go backward!!!!

I gotta get a life.

[AskBud]

Before my math problem creates a life of its own, re visit post #9. The answer is hidden in "White" text. Just highlight the post and the solution appears!

I don't want to hijack the actual purpose of the thread!
AskBud

[bluecobra]

Before my math problem creates a life of its own, re visit post #9. The answer is hidden in "White" text. Just highlight the post and the solution appears!

I don't want to hijack the actual purpose of the thread!
AskBud

I read your answer and it is incorrect in relation to the original question asked as there is no time element put into place for the 2 mile or 60MPH avg to take place in.

60mph is a unit of speed (velocity), not time.

For example, there is no limitation to somebody speeding up to 120mph to make up "time" before the 2 mile marker comes up.

[bergerud]

I read your answer and it is incorrect in relation to the original question asked as there is no time element put into place for the 2 mile or 60MPH avg to take place in.

60mph is a unit of speed (velocity), not time.

For example, there is no limitation to somebody speeding up to 120mph to make up "time" before the 2 mile marker comes up.

Bud is correct. It is a matter of definition. The average of 30 and 90 is 60 as numbers but not as speeds. The average speed is defined as the total distance divided by the total time. It is not a simple number but a rate which involves time. To calculate average speed, you need a weighted average. For example, if I go at 30 mph for 1 hour and then at 60 mph for 2 hours, the average speed is

((1)(30)+(2)(60))/(1+2)=50.

Note that this is just total distance divided by total time.